Bianca Rae B. Sambo Problem 1.4 (Classical Electrodynamics, 3rd Edition by Jackson) Each of the three charged spheres of radius a has a total charge Q. One is conducting, one has a uniform charge density within its volume and one having a spherically symmetric charge density that varies radially as where (r>-3). Use Gauss’ [...]
Solving for the electric field using Gauss’ theorem
Monday, July 4th, 2011Posted in Electrodynamics | No Comments »
Prove Green’s Reciprocation Theorem
Monday, July 4th, 2011Author: Kayrol Ann B. Vacalares MS-Physics 1, MSU-Iligan Institute of Technology ______________________________________________________________ Prove Green’s Reciprocation Theorem: If is the potential due to a volume-charge density within a volume V and a surface charge density on the conducting surface S bounding the volume V, while is the potential due to another charge distribution and , [...]
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Proving Vector Identity Using Levi-Civita Symbol
Tuesday, June 28th, 2011Roel N. Baybayon MSPhysics1 ————————————————————————————————– We are going to prove the following vector identity using Levi-Civita symbol: Solution: Let , , , . Then, By definition: We have to let m=n so that, Levi-Civita symbol can be expressed in terms of Kronecker delta given by: Thus, Share and [...]
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Verifying vector formulas using Levi-Civita: (Divergence & Curl of normal unit vector n)
Tuesday, June 28th, 2011By Sim P. Bantayan, MS Physics I, MSU-IIT Let , and where and . 1. Prove that . Proof: Now, . Since i=j for the divergence of normal unit vector n, but (i=j). Moreover, for three dimensions, , so Therefore, . 2. Prove that . Proof: . Since i=j for the curl of normal unit vector n, [...]
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Prove that the Divergence of a Curl is Zero by using Levi Civita
Tuesday, June 28th, 2011Author: Kayrol Ann B. Vacalares The divergence of a curl is always zero and we can prove this by using Levi-Civita symbol. The Levi-Civita symbol, also called the permutation symbol or alternating symbol, is a mathematical symbol used in particular in tensor calculus. Prove that: = 0 Proof: Let: and To show that: = 0 First, Here are the possible [...]
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