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		<title>Schwarz Inequality</title>
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		<pubDate>Thu, 23 Apr 2009 09:04:10 +0000</pubDate>
		<dc:creator>debbieclaire</dc:creator>
				<category><![CDATA[Quantum Science Philippines]]></category>
		<category><![CDATA[Amandus]]></category>
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		<category><![CDATA[Axiom]]></category>
		<category><![CDATA[Axioms]]></category>
		<category><![CDATA[Cauchy Schwarz Inequality]]></category>
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		<category><![CDATA[Exercise 1]]></category>
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		<category><![CDATA[Schwarz Inequality]]></category>
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		<description><![CDATA[// --&#62; Schwarz Inequality, also known as Cauchy–Schwarz inequality, Cauchy inequality, or the Cauchy–Schwarz–Bunyakovsky inequality, is useful in many Mathematical fields such as Linear Algebra. This Inequality was formulated by Augustin Cauchy (1821), Viktor Yakovlevich Bunyakovsky (1859) and Hermann Amandus Schwarz (1888). The uncertainty principle of quantum mechanics, which relates the incompatibility of two operators, [...]]]></description>
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<p>Schwarz Inequality, also known as Cauchy–Schwarz inequality, Cauchy inequality, or the Cauchy–Schwarz–Bunyakovsky inequality, is useful in many Mathematical fields such as Linear Algebra. This Inequality was formulated by Augustin Cauchy (1821), Viktor Yakovlevich Bunyakovsky (1859) and Hermann Amandus Schwarz (1888).</p>
<p>The uncertainty principle of quantum mechanics, which relates the incompatibility of two operators, rests on this important theorem of Schwarz.</p>
<p>This is a theorem that arise from the inner product of two vectors which sates that the square magnitude of the inner product of two vectors is less than or equal to the product of the square magnitude of any vector, i. e.,<br />
<center></p>
<p style="center;"><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_disc1gif.png"><img class="alignnone size-medium wp-image-558" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_disc1gif.png" alt="" width="163" height="21" /></a></p>
<p><a href="http://www.quantumsciencephilippines.com/images/schwarzinequality_p2_itm3_img(1).gif"> </a></center></p>
<p>where <a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/giflatex.gif"><img class="alignnone size-medium wp-image-556" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/giflatex.gif" alt="" width="13" height="14" /></a> and <a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/giflatex1.gif"><img class="alignnone size-medium wp-image-557" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/giflatex1.gif" alt="" width="14" height="16" /></a> are any vectors which obey the four axioms of inner product. The four axioms are:</p>
<p><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/axiom1.gif"><img class="aligncenter size-medium wp-image-191" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/axiom1.gif" alt="" width="97" height="18" /></a></p>
<p><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/axiom2.gif"><img class="aligncenter size-medium wp-image-192" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/axiom2.gif" alt="" width="147" height="19" /></a></p>
<p style="center;"><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_axiom3gif.png"><img class="alignnone size-medium wp-image-554 aligncenter" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_axiom3gif.png" alt="" width="297" height="18" /></a></p>
<p style="center;"><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_axiom4gif.png"><img class="alignnone size-medium wp-image-555" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/04/p2_axiom4gif-300x17.png" alt="" width="300" height="17" /></a></p>
<p>where α and β are scalar constants.</p>
<p>Exercise (1):</p>
<p>By going through the derivation of Schwarz Inequality, show that the inequality becomes an equality if</p>
<p><a href="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/condition.gif"><img class="aligncenter size-medium wp-image-198" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/03/condition.gif" alt="" width="60" height="20" /></a></p>
<p>where μ is an arbitrary constant.</p>
<p>Solution:</p>
<p>Starting with the Schwarz Inequality</p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(1).gif" alt="" width="142" height="18" /></p>
<p style="center;">with the general equation</p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(2).gif" alt="" width="153" height="42" /></p>
<p>From the axiom;</p>
<p><img class="alignnone" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(3).gif" alt="" width="73" height="17" /></p>
<p>we let the axiom equal to zero and substitute the value V so then we have,</p>
<p><img class="alignnone" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(4).gif" alt="" width="73" height="17" /></p>
<p><img class="alignnone" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(5).gif" alt="" width="288" height="41" /></p>
<p><img class="alignnone" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(6).gif" alt="" width="503" height="40" /></p>
<p><img class="alignnone" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(7).gif" alt="" width="151" height="41" /></p>
<p>Doing algebra and simple transformation we arrive to the equation</p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(8).gif" alt="" width="163" height="20" /></p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(9).gif" alt="" width="134" height="19" /></p>
<p>and from the general equation we have, we derived this</p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(10).gif" alt="" width="120" height="42" /></p>
<p>with the condition</p>
<p style="center;"><img class="alignnone aligncenter" src="http://www.quantumsciencephilippines.com/images/schwarz-inequality/schwarzinequality_p2_itm3_img(11).gif" alt="" width="161" height="40" /></p>
<p style="center;">About the Author</p>
<p style="center;">Debbie Claire R. Sanchez is currently a student of MSU-IIT pursuing her graduate study and hopefully will be graduating soon. She is very much interested in the field of Materials Science more specifically on Polymers. She plans to pursue her Ph. D in the United States and dreams on working in a well known company.</p>

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		<title>Basics of Linear Vector Spaces</title>
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		<pubDate>Sun, 18 Jan 2009 16:41:53 +0000</pubDate>
		<dc:creator>iitquantum</dc:creator>
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		<description><![CDATA[by CARIEL O. MONTALBAN In quantum mechanics, I have learned that the wavefunctions, , reside in Hilbert&#8217;s space.  What is Hilbert&#8217;s space? I guess to answer this question requires exploring the basic  properties of Hilbert&#8217;s space. Hilbert&#8217;s space is a linear vector space whose elements, entities or components obey certain rules or axioms.  This means [...]]]></description>
			<content:encoded><![CDATA[<p><span style="color: #993300;"><strong>by CARIEL O. MONTALBAN</strong></span></p>
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<p>In quantum mechanics, I have learned that the wavefunctions, <img class="alignnone size-medium wp-image-76" style="vertical-align: bottom;" title="the wavefunction" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/01/psi_xyzt_symbol.png" alt="" width="100" height="18" />, reside in Hilbert&#8217;s space.  What is Hilbert&#8217;s space? I guess to answer this question requires exploring the basic  properties of Hilbert&#8217;s space.</p>
<p>Hilbert&#8217;s space is a linear vector space whose elements, entities or components obey certain rules or axioms.  This means firstly than you can add these elements and the resulting sum is also as a member or entity of  that  space. Secondly, you can multiply the elements with any arbitrary scalar and the product yields something which is also a component of that same space.  Additionally, the operations of addition and multiplication obey definite rules. These rules are called axioms for addition and multiplication.</p>
<p>By means of simple problems discussed below, I illustrate these axioms which are obeyed by a linear vector space and to which the wavefunctions,<img class="alignnone size-medium wp-image-76" style="vertical-align: bottom;" title="the wavefunction" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/01/psi_xyzt_symbol.png" alt="" width="100" height="18" /> , of quantum mechanics  belongs.</p>
<p>As a simple example, let us consider the set of all entities of the form <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> where <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abcs.gif" alt="" width="45" height="18" /> are real numbers. Do these form a linear vector space? First, we have know how these elements are added and how they multiply with scalars. If their addition and multiplication are defined respectively as follows:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn1.GIF" alt="" />;</div>
<p>and</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/linear-vector-space-alpha.gif" alt="" width="200" height="20" />,</div>
<p>we can then verify that the axioms required for a linear vector space are satisfied in this case.</p>
<p>From the addition operation, we can write the null vector of the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> as:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn2.GIF" alt="" />.</div>
<p>Also from the multiplication operation, we can then write down the inverse of <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> simply as  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abcminus.gif" alt="" width="80" height="18" />.</p>
<p>We can now verify that all four axioms for addition of elements of the set  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> are satisfied.</p>
<p><span style="color: #993300;"><strong>First Axiom: Commutativity Property</strong></span></p>
<p>The operation of addition in a linear vector space is commutative; which means that we don&#8217;t care about the order in which the elements are added because we always get the same result.  This axiom is written as:</p>
<div align="center">(i) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn3.GIF" alt="" /></div>
<p>Our proof is as follows. Let <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn4.GIF" alt="" /> and <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn5.GIF" alt="" />.</p>
<p>Then,</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn6.GIF" alt="" />.</div>
<p>Thus in a linear vector, the addition of vectors is commutative.</p>
<p><span style="color: #993300;"><strong>Second Axiom: Associative Property</strong></span></p>
<p>The operation of addition in a linear vector space is associative which means that we don&#8217;t care about the order in which two elements are added to the third one because we always get the same result. This axiom is expressed as:</p>
<div align="center">(ii) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn7.GIF" alt="" />.</div>
<p>To prove this in the case of the set , we let <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn8.GIF" alt="" /></p>
<p>Then,</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn9.GIF" alt="" />.</div>
<p>Therefore the addition of vectors in a linear vector space is associative.</p>
<p><span style="color: #993300;"><strong>Third Axiom: Existence of an identity element</strong></span></p>
<p>The third requirement for a set to be a linear vector space is that the identity element exists. The identity element is defined as</p>
<div align="center">(iii) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn10.GIF" alt="" />.</div>
<p>The identity element of the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> is therefore none other than the null vector <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn2.GIF" alt="" /></p>
<p>To show this property, we just apply the definition of addition hence</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn11.GIF" alt="" />.</div>
<p><span style="color: #993300;"><strong>Fourth Axiom: Existence of an inverse</strong></span></p>
<p>The inverse of a vector should exist in a linear vector space. The inverse is defined by the statement</p>
<div align="center">(iv)  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn12.GIF" alt="" />.</div>
<p>For the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> we can then verify the existence of an inverse as follows:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn13.GIF" alt="" /></div>
<p><span style="color: #993300;"><strong>Examples of non-vector spaces</strong></span></p>
<p>From the four axioms of addition of linear vector space, we can further make the following observations.</p>
<p>(1) If <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> are required to be positive numbers, we can&#8217;t construct a vector space because Axiom (iv) will not be satisfied.</p>
<p>(2) The vectors of the form <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-ab1.gif" alt="" width="50" height="18" /> do not form a linear vector space. To show this, we let</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn14.GIF" alt="" /></div>
<p>where <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-a1b1.gif" alt="" width="75" height="16" /> are all real numbers.</p>
<p>Then by Axiom (i),</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn16.GIF" alt="" />.</div>
<p>Thus, <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-ab1.gif" alt="" width="50" height="18" /> does not form a linear vector space. The closure property is clearly violated since</p>
<p><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn17.GIF" alt="" />.</p>
<p><br/><br />
<strong>About the Author:</strong><br/><br />
<span style="color: #993300;"><strong>CARIEL O. MONTALBAN</strong></span> finished his B.S. in Physics from Mindanao State University-Iligan Institute of Technology (MSU-IIT), Iligan City, Philippines in March 2008 and is now a graduate student of the same university.  He hopes to become an active researcher in the field of experimental physics in the future.</p>

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