By Euprime B. Regalado From Gauss theorem, we can show that the surface of a curved charged conductor, the normal derivative of the electric field is given by where and are the principal radii of curvature of the surface. Gauss’s law in integral form is expressed as when there are no charges enclosed in the […]

## Archive for July, 2011

### The Normal Derivative Of Electric Field

Monday, July 4th, 2011Posted in Electrodynamics **|** No Comments »

### Solving for the distribution of charge where time-averaged potential is given

Monday, July 4th, 2011by Sim P. Bantayan, MSPhysics I, MSU-IIT Problem 1.5 The time-averaged potential of a neutral hydrogen atom is given by where q is the magnitude of the electronic charge, and being the Bohr radius. Find the distribution of charge( both continuous and discrete) that will give this potential and interpret your result physically. […]

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### Electrostatic Energy and Energy Densities of Different Capacitors

Monday, July 4th, 2011Electrostatic Energy and Energy Densities of Different Capacitors Author: Quennie J. Paylaga, Master of Science in Physics student Problem 1.8 (Chapter 1 of Classical Electrodynamics 3rd Edition by JD Jackson) Calculate the electrostatic energy (express it in terms of equal and opposite charges Q and -Q placed on the conductors and the potential difference between […]

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### Solving for the electric field using Gauss’ theorem

Monday, July 4th, 2011Bianca Rae B. Sambo Problem 1.4 (Classical Electrodynamics, 3rd Edition by Jackson) Each of the three charged spheres of radius a has a total charge Q. One is conducting, one has a uniform charge density within its volume and one having a spherically symmetric charge density that varies radially as where (r>-3). Use Gauss’ […]

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### Mean Value Theorem (Classical Electrodynamics)

Monday, July 4th, 2011Roel N. Baybayon MSPhysics1-MSU-IIT ————————————————————————————— Problem 1.10 Prove the mean value theorem: For charge-free space the value of the electrostatic potential at any point is equal to the average of the potential over the surface of any sphere centered on that point. Proof: To prove this problem, we are going to use the Green’s […]

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