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		<title>Basics of Linear Vector Spaces</title>
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				<category><![CDATA[Quantum Science Philippines]]></category>
		<category><![CDATA[linear vector space]]></category>
		<category><![CDATA[quantum physics]]></category>
		<category><![CDATA[addition]]></category>
		<category><![CDATA[Addition Of Vectors]]></category>
		<category><![CDATA[Array]]></category>
		<category><![CDATA[associativity]]></category>
		<category><![CDATA[Axiom]]></category>
		<category><![CDATA[Axioms]]></category>
		<category><![CDATA[axioms of linear vector space]]></category>
		<category><![CDATA[closure property]]></category>
		<category><![CDATA[Commutative]]></category>
		<category><![CDATA[commutativity]]></category>
		<category><![CDATA[Definite Rules]]></category>
		<category><![CDATA[Elements]]></category>
		<category><![CDATA[Entities]]></category>
		<category><![CDATA[examples of non-vector spaces]]></category>
		<category><![CDATA[Firstly]]></category>
		<category><![CDATA[Guess]]></category>
		<category><![CDATA[inverse of a vector]]></category>
		<category><![CDATA[Linear Vector Spaces]]></category>
		<category><![CDATA[Montalban]]></category>
		<category><![CDATA[Multiplication]]></category>
		<category><![CDATA[Multiplication Operation]]></category>
		<category><![CDATA[Multiplication Problems]]></category>
		<category><![CDATA[Null]]></category>
		<category><![CDATA[null vector]]></category>
		<category><![CDATA[Product Yields]]></category>
		<category><![CDATA[Proof]]></category>
		<category><![CDATA[quantum mechanics]]></category>
		<category><![CDATA[Real Numbers]]></category>
		<category><![CDATA[Scalar Multiplication]]></category>
		<category><![CDATA[Scalars]]></category>
		<category><![CDATA[Vector Addition]]></category>
		<category><![CDATA[Vector Space]]></category>
		<category><![CDATA[Vectors]]></category>

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		<description><![CDATA[by CARIEL O. MONTALBAN





In quantum mechanics, I have learned that the wavefunctions, , reside in Hilbert&#8217;s space.  What is Hilbert&#8217;s space? I guess to answer this question requires exploring the basic  properties of Hilbert&#8217;s space.
Hilbert&#8217;s space is a linear vector space whose elements, entities or components obey certain rules or axioms.  This means firstly than [...]]]></description>
			<content:encoded><![CDATA[<p><span style="color: #993300;"><strong>by CARIEL O. MONTALBAN</strong></span></p>
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<p>In quantum mechanics, I have learned that the wavefunctions, <img class="alignnone size-medium wp-image-76" style="vertical-align: bottom;" title="the wavefunction" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/01/psi_xyzt_symbol.png" alt="" width="100" height="18" />, reside in Hilbert&#8217;s space.  What is Hilbert&#8217;s space? I guess to answer this question requires exploring the basic  properties of Hilbert&#8217;s space.</p>
<p>Hilbert&#8217;s space is a linear vector space whose elements, entities or components obey certain rules or axioms.  This means firstly than you can add these elements and the resulting sum is also as a member or entity of  that  space. Secondly, you can multiply the elements with any arbitrary scalar and the product yields something which is also a component of that same space.  Additionally, the operations of addition and multiplication obey definite rules. These rules are called axioms for addition and multiplication.</p>
<p>By means of simple problems discussed below, I illustrate these axioms which are obeyed by a linear vector space and to which the wavefunctions,<img class="alignnone size-medium wp-image-76" style="vertical-align: bottom;" title="the wavefunction" src="http://www.quantumsciencephilippines.com/wp-content/uploads/2009/01/psi_xyzt_symbol.png" alt="" width="100" height="18" /> , of quantum mechanics  belongs.</p>
<p>As a simple example, let us consider the set of all entities of the form <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> where <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abcs.gif" alt="" width="45" height="18" /> are real numbers. Do these form a linear vector space? First, we have know how these elements are added and how they multiply with scalars. If their addition and multiplication are defined respectively as follows:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn1.GIF" alt="" />;</div>
<p>and</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/linear-vector-space-alpha.gif" alt="" width="200" height="20" />,</div>
<p>we can then verify that the axioms required for a linear vector space are satisfied in this case.</p>
<p>From the addition operation, we can write the null vector of the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> as:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn2.GIF" alt="" />.</div>
<p>Also from the multiplication operation, we can then write down the inverse of <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> simply as  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abcminus.gif" alt="" width="80" height="18" />.</p>
<p>We can now verify that all four axioms for addition of elements of the set  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> are satisfied.</p>
<p><span style="color: #993300;"><strong>First Axiom: Commutativity Property</strong></span></p>
<p>The operation of addition in a linear vector space is commutative; which means that we don&#8217;t care about the order in which the elements are added because we always get the same result.  This axiom is written as:</p>
<div align="center">(i) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn3.GIF" alt="" /></div>
<p>Our proof is as follows. Let <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn4.GIF" alt="" /> and <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn5.GIF" alt="" />.</p>
<p>Then,</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn6.GIF" alt="" />.</div>
<p>Thus in a linear vector, the addition of vectors is commutative.</p>
<p><span style="color: #993300;"><strong>Second Axiom: Associative Property</strong></span></p>
<p>The operation of addition in a linear vector space is associative which means that we don&#8217;t care about the order in which two elements are added to the third one because we always get the same result. This axiom is expressed as:</p>
<div align="center">(ii) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn7.GIF" alt="" />.</div>
<p>To prove this in the case of the set , we let <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn8.GIF" alt="" /></p>
<p>Then,</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn9.GIF" alt="" />.</div>
<p>Therefore the addition of vectors in a linear vector space is associative.</p>
<p><span style="color: #993300;"><strong>Third Axiom: Existence of an identity element</strong></span></p>
<p>The third requirement for a set to be a linear vector space is that the identity element exists. The identity element is defined as</p>
<div align="center">(iii) <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn10.GIF" alt="" />.</div>
<p>The identity element of the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> is therefore none other than the null vector <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn2.GIF" alt="" /></p>
<p>To show this property, we just apply the definition of addition hence</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn11.GIF" alt="" />.</div>
<p><span style="color: #993300;"><strong>Fourth Axiom: Existence of an inverse</strong></span></p>
<p>The inverse of a vector should exist in a linear vector space. The inverse is defined by the statement</p>
<div align="center">(iv)  <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn12.GIF" alt="" />.</div>
<p>For the set <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> we can then verify the existence of an inverse as follows:</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn13.GIF" alt="" /></div>
<p><span style="color: #993300;"><strong>Examples of non-vector spaces</strong></span></p>
<p>From the four axioms of addition of linear vector space, we can further make the following observations.</p>
<p>(1) If <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-abc.gif" alt="" width="50" height="18" /> are required to be positive numbers, we can&#8217;t construct a vector space because Axiom (iv) will not be satisfied.</p>
<p>(2) The vectors of the form <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-ab1.gif" alt="" width="50" height="18" /> do not form a linear vector space. To show this, we let</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn14.GIF" alt="" /></div>
<p>where <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-a1b1.gif" alt="" width="75" height="16" /> are all real numbers.</p>
<p>Then by Axiom (i),</p>
<div align="center"><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn16.GIF" alt="" />.</div>
<p>Thus, <img class="alignnone-medium wp-image-76" style="vertical-align: bottom;" src="http://www.quantumsciencephilippines.com/images/linear-vector-space-ab1.gif" alt="" width="50" height="18" /> does not form a linear vector space. The closure property is clearly violated since</p>
<p><img src="http://www.quantumsciencephilippines.com/images/HilbertSpace1_eqn17.GIF" alt="" />.</p>
<p><br/><br />
<strong>About the Author:</strong><br/><br />
<span style="color: #993300;"><strong>CARIEL O. MONTALBAN</strong></span> finished his B.S. in Physics from Mindanao State University-Iligan Institute of Technology (MSU-IIT), Iligan City, Philippines in March 2008 and is now a graduate student of the same university.  He hopes to become an active researcher in the field of experimental physics in the future.</p>

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