Radial Wavefunction of a Hydrogen Atom | Quantum Science Philippines
Quantum Science Philippines

Radial Wavefunction of a Hydrogen Atom

Gibson T. Maglasang and John Paul Aseniero

In this article, we outlined the necessary steps in calculating the radial wavefunctions R_{nl} for the Hydrogen atom. Thus, the radial wavefunctions particularly R_{30 , R_{31 and R_{32 are easily obtained  without bothering to normalize it.

We use the formula below to find the wavefunction,

R_{nl}=\frac{1}{r}\rho^{l+1}e^{-\rho}\nu(\rho),                                ( 1)

where

\nu(\rho)=\sum_{j=0}^{\infty}c_j\rho^j,                                         (2)

while c_j is determined by the recursion formula given by,

c_{j+1}=\frac{2(j+l+1-n)}{(j+1)(j+2l+2)}c_j,                          (3)

and

\rho=\frac{r}{na}.                                                            (4)

(i) Now, finding R_{30}

Using equation 1, we need to solve first the coefficient c_j from (eqn. 3), with n=3 and l=0.

c_1=\frac{2(0+1-3)}{1(0+0+2)}c_0=-2c_0

c_2=\frac{2(1+1-3)}{2(1+0+2)}c_1=-\frac{2}{3}c_0

c_3=\frac{2(2+1-3)}{3(2+2)}c_2=0.

Knowing the value of c_j, (eqn. 2) can now be easily determined,

\nu(\rho)=c_0\rho^0+c_1\rho^1+c_2\rho^2+c_3\rho^3.                         (5)

Substituting the value of the calculated coefficients to (eqn. 5), we then have

\nu(\rho)=c_0-2c_0+\frac{2}{3}\rho^2c_0.                                         (6)

Thus,

R_{30}(\nu)=\frac{1}{r}\Big(\frac{r}{3a}\Big)e^{-\rho}[c_0-2c_0+\frac{2}{3}c_0\rho^2].              (7)

Plugging in (eqn. 4) to (eqn. 7), we finally have

R_30=\frac{c_0}{3a}\bigg[1-2\Big(\frac{r}{3a}\Big)+\frac{2}{3}\Big(\frac{r}{3a}\Big)\rho^2\bigg]e^{-(r/3a)}.

Following the same process in (i), the rest of the wavefunctions are just straightforward.

(ii) For R_{31}

Determining first the coefficients, with n=3 and l=1,

c_1=\frac{2(1+1-3)}{1(0+2+2)}c_0=-\frac{1}{2}c_0

c_2=\frac{2(1+1+1-3)}{2(1+2+2)}c_0=0

c_3=0

Then,

\nu(\rho)=c_0-\frac{1}{2}c_0\rho.

Thus,

R_{31}=\Big(\frac{r}{9a^2}\Big)\bigg[1-\frac{r}{6a}\bigg]e^{-r/3a}

(iii) We have the coefficients for R_{32} with n=3 and l=2,

c_1=\frac{2(2+1-3)}{1(4+2)}c_0=0

c_2=0

c_3=0

Using again (eqn. 1), we have

R_{32}=\frac{r^2}{27a^3}e^{-r/2a}c_0

We finally generated the radial wavefunctions (R_{30}, R_{31}, R_{32}) for the hydrogen atom which is the main aim of this paper.

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